I am curious as to the output of the cutting force guage, is this based on the radius of the tool being used? I.E. if i have a 0.500" endmill and the cut outputs 45.9 lb in the cutting force gauge can i assume this to equate to 45.9\48 = 0.956 ftlbs of torque?
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Eldar Gerfanov (Admin)
Hello, Cutting force is the result of multiplying the torque by the radius of the end mill. The results box shows both the cutting force and the torque. This value, like many others, is purely theoretical average and does not consider dynamic properties of the cut.
ryan4946
Alright, that makes sense. Thank you again Eldar, its a beautiful tool youve created, i had just noticed the change between an old version i had on my laptop and the new version on my CAD\CAM seat and wanted to make sure i understood it correctly.